Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-3 Operations With Radical Expressions - Practice and Problem-Solving Exercises - Page 629: 28

Answer

The answer is $-\sqrt6$.

Work Step by Step

We can simplify the expression as follows: $=(\sqrt6+\sqrt3)(\sqrt2-2)$ $=\sqrt6*\sqrt2-\sqrt6*2+\sqrt3*\sqrt2-\sqrt3*2$ $=\sqrt12-2\sqrt6+\sqrt6-2\sqrt3$ $=(\sqrt4*\sqrt3)-\sqrt6-2\sqrt3$ $=2\sqrt3-\sqrt6-2\sqrt3$ $=-\sqrt6$.
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