Chapter 10 - Radical Expressions and Equations - 10-3 Operations With Radical Expressions - Practice and Problem-Solving Exercises - Page 629: 21

$2\sqrt3+3\sqrt 2$

We can simplify the product as follows: = $\sqrt 6(\sqrt 2+\sqrt 3)$ = $(\sqrt 2*\sqrt3)(\sqrt 2+\sqrt 3)$ = $(\sqrt 2*\sqrt3)*\sqrt 2+(\sqrt 2*\sqrt3)*\sqrt 3$ = $2\sqrt3+3\sqrt 2$ (since $\sqrt x * \sqrt y = \sqrt xy$)