Answer
$3, 12, 27$
Work Step by Step
Let $x$ be the number whose square root is of the form $a\sqrt3$
$\implies \sqrt x = a \sqrt3$
Squaring both sides
$x = a^2 \times 3$
Now we can generate any 3 numbers by replacing a with any real number.
Replacing $a$ with 1 we get x as:
$x = 3$
Replacing $a$ with 2 we get x as:
$x = 4\times 3 = 12$
Replacing $a$ with 3 we get x as:
$x = 9 \times 3 = 27$