Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-2 Simplifying Radicals - Practice and Problem-Solving Exercises - Page 624: 69

Answer

$ 8\sqrt 6a / 3a$

Work Step by Step

We can simplify the expression as follows: = $ 16a / \sqrt 6a^{3}$ = $ 16a / (\sqrt 6*\sqrt a^{2}*\sqrt a)$ = $ 16a / (\sqrt 6*a*\sqrt a)$ = $ 16 / (\sqrt 6*\sqrt a)$ = $ 16*(\sqrt 6*\sqrt a) / (\sqrt 6*\sqrt a)*(\sqrt 6*\sqrt a)$ (Multiply and divide by $(\sqrt 6*\sqrt a)$ to rationalize the denominator). = $ 16*(\sqrt 6a) / 6a$ = $ 8\sqrt (6a) / 3a$.
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