Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-2 Simplifying Radicals - Practice and Problem-Solving Exercises - Page 623: 26

Answer

$315\sqrt 2$

Work Step by Step

Solve expression and simplify: $-5\sqrt 21 \times (-3\sqrt 42)$ = $15(\sqrt 21\times \sqrt 45)$ =$ 15\sqrt 882$ Find the square factor 882= $2\times441$ = $2\times9\times49$ = $2\times 21^{2}$ So 441 is the square factor Now put it in the equation: =$ 15\sqrt 882$ =$ 15(\sqrt 2\times\sqrt 441)$ = $ 15(\sqrt 2\times\ 21)$ = $15\times21 (\sqrt 2)$ = $315 (\sqrt 2)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.