Answer
The first instruction will cause the memory location labeled L to be
loaded into register R. Because $\mathrm{L}$ contains the data value $+1,$ this will
go into $R,$ overwriting whatever was there previously. After completing
one instruction, a processor will go on to the next one unless told to
do otherwise-that is the essence of the Fetch/Decodel Execute cycle.
Thus, the processor will next try to execute the "instruction" $+1 .$ As we
explained in the text, this will be incorrectly interpreted as the op code 0
and adress field of $1,$ which is a LOAD 1. Thus, the value $+1$ in register
R will be overwritten with the contents of memory location $1 .$
Work Step by Step
The first instruction will cause the memory location labeled L to be
loaded into register R. Because $\mathrm{L}$ contains the data value $+1,$ this will
go into $R,$ overwriting whatever was there previously. After completing
one instruction, a processor will go on to the next one unless told to
do otherwise-that is the essence of the Fetch/Decodel Execute cycle.
Thus, the processor will next try to execute the "instruction" $+1 .$ As we
explained in the text, this will be incorrectly interpreted as the op code 0
and adress field of $1,$ which is a LOAD 1. Thus, the value $+1$ in register
R will be overwritten with the contents of memory location $1 .$
