Answer
Initial values $\qquad \ \ \ \ $ memory location 50= 4
$\begin{array}{ll}
{\text {Operation}} & {\text {Final Contents of Register R } } \\
{\text {LOAD L+1}} & {\text {A copy of the contents of memory cell 51. This operation} } \\
{\text {}} & {\text {means LOAD (L + 1), which is equivalent to LOAD 51.} } \\
{\text {}} & {\text {LOAD L + 1 does arithmetic on addresses, not contents.} } \\
\end{array}$
Work Step by Step
Initial values $\qquad \ \ \ \ $ memory location 50= 4
$\begin{array}{ll}
{\text {Operation}} & {\text {Final Contents of Register R } } \\
{\text {LOAD L+1}} & {\text {A copy of the contents of memory cell 51. This operation} } \\
{\text {}} & {\text {means LOAD (L + 1), which is equivalent to LOAD 51.} } \\
{\text {}} & {\text {LOAD L + 1 does arithmetic on addresses, not contents.} } \\
\end{array}$
