Answer
(a) The angular speed $\omega$ is the same for both points because both points sweep through the same angle per unit time. For example, when point A completes one full rotation, point B also completes one full rotation.
(b) Since the tangential speed $v$ is equal to $\omega r$, where $r$ is the radius, the tangential speed at point A has a larger magnitude.
(c) Since the angular acceleration is the change in $\omega$ per unit time, and $\omega$ is the same at both points, then the angular acceleration $\alpha$ is also equal at both points.
(d) Since the tangential acceleration $a$ is equal to $\alpha r$, where $r$ is the radius, the tangential acceleration has a greater magnitude at point A.
(e) Since the radial acceleration is equal to $\omega^2 r$, where $r$ is the radius, the magnitude of the radial acceleration is greater at point A.
Work Step by Step
(a) The angular speed $\omega$ is the same for both points because both points sweep through the same angle per unit time. For example, when point A completes one full rotation, point B also completes one full rotation.
(b) Since the tangential speed $v$ is equal to $\omega r$, where $r$ is the radius, the tangential speed at point A has a larger magnitude.
(c) Since the angular acceleration is the change in $\omega$ per unit time, and $\omega$ is the same at both points, then the angular acceleration $\alpha$ is also equal at both points.
(d) Since the tangential acceleration $a$ is equal to $\alpha r$, where $r$ is the radius, the tangential acceleration has a greater magnitude at point A.
(e) Since the radial acceleration is equal to $\omega^2 r$, where $r$ is the radius, the magnitude of the radial acceleration is greater at point A.
