Answer
The impulse imparted to the ball is $0.593~kg~m/s$.
Work Step by Step
We can find the initial velocity of the ball.
$v_0^2 = v^2-2ay = 0 - 2ay$
$v_0 = \sqrt{-2ay} = \sqrt{-(2)(-9.80~m/s^2)(5.50~m)}$
$v_0 = 10.4~m/s$
We can find the impulse imparted to the ball.
$J = mv = (0.0570~kg)(10.4~m/s)$
$J = 0.593~kg~m/s$
The impulse imparted to the ball is $0.593~kg~m/s$.
