Answer
(a) $P = 1.20\times 10^5~kg~m/s$
(b) (i) $v = 60.0~m/s$
(ii) $v = 26.8~m/s$
Work Step by Step
(a) $P = mv = (10,000~kg)(12.0~m/s)$
$P = 1.20\times 10^5~kg~m/s$
(b) (i) $mv = P$
$v = \frac{P}{m} = \frac{1.20\times 10^5~kg~m/s}{2000~kg}$
$v = 60.0~m/s$
(ii) We can find the kinetic energy of the truck.
$\frac{1}{2}mv^2 = \frac{1}{2}(10,000~kg)(12.0~m/s)^2$
$K = 7.20\times 10^5~J$
We can find the speed of the SUV.
$\frac{1}{2}mv^2 = K$
$v^2 = \frac{2K}{m}$
$v = \sqrt{\frac{2K}{m}}$
$v = \sqrt{\frac{(2)(7.20\times 10^5~J)}{2000~kg}}$
$v = 26.8~m/s$
