Answer
(a) please refer to free body diagram below
The tension force in the wire, which pulls up on the instrument, is greater than the instrument's weight.
(b) The force of tension in the wire is 79.6 N.
Work Step by Step
(a) please refer to free body diagram below
The tension force in the wire, which pulls up on the instrument, is greater than the instrument's weight.
(b) We can find the acceleration.
$y = \frac{1}{2}at^2$
$a = \frac{2y}{t^2} = \frac{(2)(276~m)}{(15.0~s)^2}$
$a = 2.453~m/s^2$
We can use a force equation to find the force of tension $T$ in the wire.
$\sum F = ma$
$T - mg = ma$
$T = ma + mg$
$T = (6.50~kg)(2.453~m/s^2)+(6.50~kg)(9.80~m/s^2)$
$T = 79.6~N$
The force of tension in the wire is 79.6 N.
