University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 3 - Motion in Two or Three Dimensions - Problems - Exercises - Page 99: 3.84

Answer

(b) 93 cm.

Work Step by Step

A seed is launched at 0 degrees and travels horizontally. The vertical height $h = 20cm$. The time taken to fall is $\frac{1}{2}gt^2 = 0.2 \implies t = 0.202 s$. The horizontal height $x = vt = (4.6)(0.202) = 0.93 m = 93 cm$, which is choice (b).
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