Answer
A pilot will black out at a speed of 123 m/s (275 mph) or faster.
Work Step by Step
We can set the radial acceleration equal to 5.5g.
$a_R = \frac{v^2}{R} = 5.5g$
$v^2 = 5.5gR$
$v = \sqrt{5.5gR} = \sqrt{(5.5)(9.80~m/s^2)(280~m)}$
$v = 123~m/s$
$v=(123~m/s)(\frac{3600s}{1609~mi})=275~mph$
A pilot will black out at a speed of 123 m/s (275 mph) or faster.