Answer
a) Distance = 92m
b) Displacement also 92m, as motion is in straight line displacement = distance
Work Step by Step
a) Total distance moved by the gazelle = area under velocity-time graph
= area of trapezium + area of triangle
= $\frac{1}{2}(4+12)*10 + \frac{1}{2}.12.2 = 92m$
b) Displacement of the gazelle is same as distance, since the motion is in a straight line. Which is 92m
