Answer
(a) $v_1 = 8.3 ~m/s$
(b) $a = 1.1~m/s^2$
Work Step by Step
(a) The average speed is $\frac{70.0 ~m}{6.00~s} = 11.67 ~m/s$
$\frac{v_1+v_2}{2} = 11.67 ~m/s$
$v_1 = (2)(11.67~m/s) - v_2$
$v_1 = (2)(11.67~m/s) - (15.0 ~m/s)$
$v_1 = 8.3 ~m/s$
(b) $a = \frac{\Delta v}{\Delta t} = \frac{v_2-v_1}{\Delta t}$
$a = \frac{15.0 ~m/s - 8.3~m/s}{6.00~s}$
$a = 1.1~m/s^2$