University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 10 - Dynamics of Rotational Motion - Problems - Discussion Questions - Page 328: Q10.9

Answer

The new angular acceleration will be 32 times smaller than the old one.

Work Step by Step

With each of the 3 dimensions being twice as great, the volume of the new object will be (2)(2)(2) = 8 times as great as the old object, and so will the mass. Using equation 9.16 to calculate the moment of inertia, we see that each distance $r_i$ is twice as great as before, so that increases the moment of inertia by another factor of $2^2 = 4$. Overall, the object’s moment of inertia is 32 times what it was before. The same torque is applied to both objects. $$\Sigma \tau = I\alpha$$ $$\alpha = \frac{\Sigma \tau }{I}$$ With a new moment of inertia I that is 32 times larger, the new angular acceleration will be smaller by a factor of 32.
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