University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 1 - Units, Physical Quantities, and Vectors - Problems - Discussion Questions - Page 27: Q1.10

Answer

Neither is a unit vector.

Work Step by Step

Generally vector can be shown by (Ai + Bj + Ck ) Magnitude of vector (Ai + Bj + Ck ) is given by (A^2 + B^2 + C^2 )^(1/2) In vector ( i + j + k ), A=1, B=1 and C=1 Therefore, Magnitude of vector ( i + j+k ) = (1^2 + 1^2 + 1^2 )^½= 3^(1/2) In vector (3.0 i -2.0j), A=3, B=-2 and C=0 Therefore, Magnitude of vector (3.0 i -2.0j) = 〖[3^2 +(-2)^2+0^(2 )]〗^½= 13〗^(1/2) Vector whose magnitude is 1 is called unit vector. In this question magnitudes of two vectors are not equal to 1. So, both are not unit vectors.
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