Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 1 - Introduction and Basic Concepts - Problems - Page 44: 1-64

Answer

a)$h=0.60m$ a)$h=8.15m$

Work Step by Step

No matter what fluid you use the relation of pressure will be: $P_{g}=\rho_{fluid}*g*h$ Then: $h=\frac{P_{g}}{\rho_{fluid}*g}$ a)$h=\frac{80000Pa}{(13600\frac{kg}{m^3})*(9.81\frac{m}{s^2})}=0.60m$ a)$h=\frac{80000Pa}{(1000\frac{kg}{m^3})*(9.81\frac{m}{s^2})}=8.15m$
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