Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 1 - Introduction and Basic Concepts - Problems - Page 42: 1-35E

Answer

$T(^{\circ}F) = 302^{\circ}F$ $T(R) = 762R$

Work Step by Step

$T(^{\circ}F) = 1.8T(^{\circ}C) + 32$ $T(^{\circ}F) = 1.8(150)+ 32 = 302^{\circ}F$ $T(R) = T(^{\circ}F) + 460 = 302 + 460 = 762R$
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