Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 4 - Two-Dimensional Kinematics - Problems and Conceptual Exercises - Page 110: 91

Answer

$C). 12.3m$

Work Step by Step

We know that $Y_{max}=\frac{v_{\circ}^2sin^2\theta}{2g}$ We plug in the known values to obtain: $Y_{max}=\frac{(9.92)sin^2 75.0^{\circ}}{2(3.72)}$ $Y_{max}=12.3m$
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