Answer
Please see the work below.
Work Step by Step
We can express the given vectors in unit vector notations as follows:
$\vec A=(1.5m)cos(40^{\circ})\hat x+(1.5m)sin (40^{\circ})\hat y$
$\vec A=(1.1m)\hat x+(0.96)\hat y$
The vector B can be expressed as
$\vec B=(2.0m)cos(-19^{\circ})\hat x-(2.0m)sin(-19^\circ)\hat y$
$\vec B=(1.9m)\hat x+(-0.65m)\hat y$
The vector C can be expressed as
$\vec C=(1.0m)cos(180^{\circ}-25^{\circ})+(1.0m)sin(180^{\circ}-25^{\circ})\hat y$
$\vec C=(-0.91m)\hat x+(0.42m)\hat y$
The vector D can be expressed as
$\vec D=0 \hat x+(1.5m)\hat y$