Answer
No.
Work Step by Step
Let A be the magnitude of a vector $A$:
A $=\sqrt {(A_x)^2+(A_y)^2}$. But, $(A_x)^2\geq0$ and $(A_y)^2\geq0$.
If A $=0$, we must have $A_x=0$ and $A_y=0$.
If $A_x\ne0$ or $A_y\ne0$ then A $\gt0$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 3 - Vectors in Physics - Conceptual Questions - Page 76: 6
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