Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 1 - Introduction to Physics - Problems and Conceptual Exercises - Page 17: 48

Answer

(a) $2.3~g=2.3\times10^{-3}~kg$ (b) $4.7\times10^{3}~min$

Work Step by Step

(a) $1~day=24~h$ and $1~h=60~min$. So, $1~day=24\times60min=1440~min$ $growth~rate=1.6~mg/min$ and $1~mg=10^{-3}~g=10^{-6}~kg$ $mass~increase=(growth~rate)(time)=(1.6~mg/min)(1440~min)=2.3\times10^{3}~mg=2.3~g=2.3\times10^{-3}~kg$ (b) $0.0075~kg=7500~mg$ Rearrange the equation above: $time=\frac{mass~increase}{growth~rate}=\frac{7500~mg}{1.6~mg/min}=4.7\times10^{3}~min$
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