Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 1 - Introduction to Physics - Problems and Conceptual Exercises - Page 15: 11

Answer

F = [ML$T^{-2}$]

Work Step by Step

Basically, a $\propto \dfrac{F}{m}$. So a = k $\dfrac{F}{m}$, where k is a dimensionless constant. Dimension of acceleration is [L$T^{-2}$]. Dimension of mass is [M]. Writing the above equation dimensionally gives [L$T^{-2}$] = F [$M^{-1}$]. Both sides have the same dimensions, and, therefore, F = [ML$T^{-2}$].
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