Answer
(a) $10^{8}~s$
(b) $10^{4}~s$
(c) $10^{0}~s$
(d) $10^{17}~s$
(e) $10^{10}~s$
Work Step by Step
Notice that you must not compute in order to find how many seconds there are in a year, in a baseball game, etc.
I think that we should start with the baseball game. Its average length is around $3~hours\approx10^{4}~s$. Then, you estimate that there is time for $10^{4}$ consecutive baseball games, in a year. So $a~year\approx10^{4}\times10^{4}~s=10^{8}~s$. The duration of a heartbeat is around $1~s=10^{0}~s$. Earth is around 4.5 billion years old. $1~billion=10^{9}$, so the age of the $Earth\approx10^{9}\times10^{8}~s=10^{17}~s$. The age of a person $\approx10^{2}$ years. So, $10^{2}\times10^{8}~s=10^{10}~s$
