Answer
Since $R_2 \lt R_1$, then $R_2$ dissipates the larger amount of power.
Work Step by Step
We can write an expression for the power:
$P = \frac{V^2}{R}$
Since the potential difference $V$ is the same across each resistor, the resistor with the lower resistance dissipates more power. Since $R_2 \lt R_1$, then $R_2$ dissipates the larger amount of power.
