Answer
The maximum mass of ethyl alcohol that could be boiled is 1.0 gram.
Work Step by Step
The heat energy $Q$ required to change the temperature of a substance is:
$Q = m~c~\Delta T$
The heat energy $Q$ required to change the state of a substance is:
$Q = m~L$
We can find the maximum mass of ethyl alcohol that could be boiled.
$Q = m~c~\Delta T + m~L$
$m = \frac{Q}{c~\Delta T+L}$
$m = \frac{1000~J}{(2400~J/kg~C^{\circ})(78~^{\circ}C-20~^{\circ}C)+(8.50\times 10^5~J/kg)}$
$m = 0.0010~kg = 1.0~g$
The maximum mass of ethyl alcohol that could be boiled is 1.0 gram.
