Answer
(a) $T_2 = T_1$
(b) $P_2 = \frac{P_1}{2}$
Work Step by Step
(a) Since this is an isothermal process, the temperature does not change. Therefore, $T_2 = T_1$.
(b) We can find an expression for the initial pressure as:
$P_1V_1 = nRT_0$
$P_1 = \frac{nRT_1}{V_1}$
We can find the new pressure as:
$P_2V_2 = nRT_2$
$P_2 = \frac{nRT_2}{V_2}$
$P_2 = \frac{nRT_1}{2V_1}$
$P_2 = \frac{1}{2}~\frac{nRT_1}{V_1}$
$P_2 = \frac{1}{2}~P_1$
