Answer
(a) $x = 7~m$
(b) $v = 7~m/s$
(c) $a = 4~m/s^2$
Work Step by Step
(a) $x(t) = 2t^2 -t+1$
At t = 2 s:
$x = (2)(2~s)^2-(2~s)+1$
$x = 7~m$
(b) $v(t) = \frac{dx}{dt} = 4t-1$
At t = 2 s:
$v = (4)(2~s)-1$
$v = 7~m/s$
(c) $a(t) = \frac{dv}{dt} = 4$
At t = 2 s:
$a = 4~m/s^2$