Answer
The sports car can navigate the curve at a maximum speed of $23.8m/s$
Work Step by Step
Multiple-Concept Example 8 gives us this equation: $$v=\sqrt{rgS}$$
$v$: the maximum speed a car can negotiate the curve without rolling over
$r$: the radius of the curve
$g$: gravitational acceleration
$S$: static stability factor
We have $$\frac{v_{sport}}{v_{suv}}=\frac{\sqrt{rgS_{sport}}}{\sqrt{rgS_{suv}}}=\sqrt{\frac{S_{sport}}{S_{suv}}}$$ $$v_{sport}=v_{suv}\sqrt{\frac{S_{sport}}{S_{suv}}}$$
We have $v_{suv}=18m/s$, $S_{sport}=1.4$ and $S_{suv}=0.8$
$$v_{sport}=23.8m/s$$
