Answer
a) $\tau=1.35\times10^4N.m$
b) $\tau=1.32\times10^5N.m$
Work Step by Step
a) As shown in the figure below, the lever arm between the force $W$ and the axis of rotation is $l_W=(2.5m)\sin32=1.32m$
As $W=10200N$, the torque produced by the engine's weight is $$\tau_W=Wl_W=1.35\times10^4N.m$$
b) As we can see in the figure below, the lever arm between the force $T$ and the axis of rotation is $l_T=(2.5m)\cos32=2.12m$
As $T=62300N$, the torque produced by the thrust is $$\tau_T=Tl_T=1.32\times10^5N.m$$
