Answer
c) is correct.
Work Step by Step
$F_3$ has 2 components $F_{3x}$ and $F_{3y}$.
$F_{3x}$ and $F_1$ have the same magnitude but opposite direction, so $\sum F_{x}=F_{3x}-F_1=0$
Similarly, $F_{3y}$ and $F_2$ have the same magnitude but opposite direction, so $\sum F_{y}=F_{3y}-F_2=0$
Because all the net translational forces are zero, the box will not have a translational acceleration.
All three forces $F_1, F_2$ and $F_3$ produce torques rotating in clockwise direction, so the torques cannot eliminate one another and $\sum\tau\ne0$. Therefore, the box will have rotational acceleration.
c) is correct.
