Answer
$a=9.35m/s^2$
Work Step by Step
We know the turn's radius $r=23.5m$ and the angular speed at a certain time is $\omega=0.571rad/s$
This gives us the centripetal acceleration $a_c=r\omega^2=7.66m/s^2$
At that time, the total acceleration $\vec{a}$ makes an angle of $35^o$ with the radius. Since $\vec{a_{c}}$ points in the same direction with the radius, the angle between $\vec{a}$ and $\vec{a_c}$ is $35^o$
This means $$\frac{a_c}{a}=\cos35$$ $$a=\frac{a_c}{\cos35}=9.35m/s^2$$
