Answer
b) is correct.
Work Step by Step
We have $\omega_0=5rad/s$, $\omega=9rad/s$ and $t=3s$
The angular displacement of the wheel is $$\theta=\Big(\frac{\omega_0+\omega}{2}\Big)t=21rad$$
Physics (10th Edition)
by Young, David; Stadler, Shane
Published by
Wiley
ISBN 10:
1118486897
ISBN 13:
978-1-11848-689-4
Chapter 8 - Rotational Kinematics - Focus On Concepts - Page 211: 6
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