Answer
$W_{wave}=1043J$
Work Step by Step
According to the work-energy theorem, $$W_{nc}=E_f-E_0$$ $$W_{nc}=(\frac{1}{2}mv_f^2+mgh_f)-(\frac{1}{2}mv_0^2+mgh_0)$$ $$W_{nc}=\frac{1}{2}m(v_f^2-v_0^2)+mg(h_f-h_0)$$
We know $v_0=1.4m/s$, $v_f=9.5m/s$, $h_f-h_0=-2.7m$ and $m=59kg$. Therefore, $$W_{wave}=1043J$$
