Answer
(a) $W=2982J$
(b) $W=3290J$
Work Step by Step
(a) We have $T=94N$, $s=35m$ and $\theta=25^o$
The amount of work done on the toboggan by $T$ is $$W=(T\cos\theta)s=2982J$$
(b) If $T$ is parallel to the snow, it does not make an angle with the toboggan's displacement anymore, so $\theta=0$
The amount of work done on the toboggan by $T$ is $$W=(T\cos0)s=3290J$$
