Answer
(i) Automobile A has constant acceleration.
(ii) The equations of kinematics will apply for A.
(iii) $v_A=25m/s$ and $v_B=18m/s$
Work Step by Step
(i) Automobile A has a constant acceleration. Its direction is always ahead and its magnitude always equals $3.5m/s^2$
Automobile B does not have a constant acceleration. Though its magnitude stays the same, its direction constantly changes as B negotiates the turn so that it always points toward the center of the rotation circle.
(ii) Since automobile A has a constant $a$, the equations of kinematics will apply for A.
(iii) Calculations:
- Automobile A: initial speed $v_0=18m/s$ and $a=3.5m/s^2$. At $t=2$, its speed will be
$$v=v_0+at=25m/s$$
- Automobile B: its speed stays constant, so at $t=2$, $v=18m/s$
