Answer
(a) The acceleration with which Robin Hood is pulled up is $4.25m/s^2$
(b) The tension in the rope is $1082N$
Work Step by Step
The chandelier is under the influence of 2 forces:
- Its weight $mg=195\times9.8=1911N$
- The tension in the rope $T$, in opposite direction
We assume the chandelier falls with acceleration $a$, so we have $$mg-T=ma$$ $$1911-T=195a\hspace{2cm}(1)$$
Robin Hood is also under the influence of 2 forces:
- His weight $mg=77\times9.8=754.6N$
- The tension in the rope $T$, in opposite direction
Robin Hood is pulled up with similar acceleration $a$: $$T-mg=ma$$ $$T-754.6=77a\hspace{2cm}(2)$$
Solving (1) and (2), we get $a=4.25m/s^2$ and $T=1082N$
