Answer
68 kg
Work Step by Step
$mg\sin\theta=f_{s}$
$\implies m=\frac{f_{s}}{g\sin\theta}=\frac{390\,N}{9.8\,m/s^{2}\times\sin 36^{\circ}}=68\,kg$
Physics (10th Edition)
by Young, David; Stadler, Shane
Published by
Wiley
ISBN 10:
1118486897
ISBN 13:
978-1-11848-689-4
Chapter 4 - Forces and Newton's Laws of Motion - Problems - Page 116: 57
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