Answer
$16\,\Omega$
Work Step by Step
$V=\frac{Energy}{Charge}=\frac{1.1\times10^{5}\,J}{Charge}=9.0\,V$
$\implies Charge=\frac{1.1\times10^{5}\,J}{9.0\,V}=1.2\times10^{4}\,C$
Current $I=\frac{Charge}{Time}=\frac{1.2\times10^{4}\,C}{(6\times3600)s}=0.56\,A$
According to Ohm's law,
$R=\frac{V}{I}=\frac{9.0\,V}{0.56\,A}=16\,\Omega$
