Answer
1.5 A
Work Step by Step
$q=ne=1.9\times10^{19}\times1.6\times10^{-19}\,C=3.0\,C$
$t=2.0\,s$
$I=\frac{q}{t}=\frac{3.0\,C}{2.0\,s}=1.5\,A$
Physics (10th Edition)
by Young, David; Stadler, Shane
Published by
Wiley
ISBN 10:
1118486897
ISBN 13:
978-1-11848-689-4
Chapter 20 - Electric Circuits - Focus On Concepts - Page 571: 1
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