Answer
second bulb has greater filament resistance
Work Step by Step
We have $ V=120V$
We know that
$P = \frac{V^2}{R}$
thus
$\frac{ P_1}{P_2} =\frac{ V^2}{R_1}*\frac{ R_2}{V^2}$
$ \frac {75}{150} =\frac{ R_2}{R_1}$
$ \implies R_1 = 2 R_2$
hence second bulb has greater filament resistance
