Answer
(b),(d) and (e)
Work Step by Step
We have
$ R = \frac{\rho l}{A} = \frac{\rho l}{\pi r^2} $
Since resistivity is constant and $\pi$ is also a constant, thus the resistor with $\frac{l}{r^2} $ maximum have maximum resistance and minimum current.
for (b) $ \frac{1}{2}L_0$ and $\frac{1}{2}r_0$, (d)$2L_0 $ and $r_0$ and (e)$8L_0$ and $ 2 r_0$, $\frac{l}{r^2} $ is maximum ($\frac{2L_0}{r_0^2}$) thus resistance is maximum and current is minimum
