Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 2 - Kinematics in One Dimension - Problems - Page 47: 1

Answer

9.1 football fields

Work Step by Step

Distance = average speed $\times$ time = (7.6 $\times$ $10^{3}$) $\times$ (110 $\times$ $10^{-3}$) = 8.36 $\times$ $10^{2}$ m Number of football fields = $\frac{distance}{length}$ = (8.36 $\times$ $10^{2}$) / 91.4 $\approx$ 9.1
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