Answer
$\sqrt 6$ $v$
Work Step by Step
$v^{2}=u^{2}+2ax$
sub $u=0$
$v^{2}=2ax$
$v=\sqrt (2ax)$
$v_{new}$
=$\sqrt (2a(3x))$
=$\sqrt (6ax)$
= $\sqrt 6\times\sqrt (2ax)$
=$\sqrt 6\times\ v$
Physics (10th Edition)
by Young, David; Stadler, Shane
Published by
Wiley
ISBN 10:
1118486897
ISBN 13:
978-1-11848-689-4
Chapter 2 - Kinematics in One Dimension - Check Your Understanding - Page 35: 12
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