Answer
2.9 $\mu F$
Work Step by Step
Charge, q= 4.3 $\mu C$
Voltage, V= 1.5 V
Thus, we find:
Capacitance, C= q/V = $\frac{4.3\times10^{-6}C}{1.5V}\approx 2.9 \mu F$
Physics (10th Edition)
by Young, David; Stadler, Shane
Published by
Wiley
ISBN 10:
1118486897
ISBN 13:
978-1-11848-689-4
Chapter 19 - Electric Potential Energy and the Electric Potential - Problems - Page 539: 42
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