Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 12 - Temperature and Heat - Problems - Page 342: 6

Answer

(a) 1.0 °A =( 11/9 ) °B (b) 40.0 °A = 48.89 °B

Work Step by Step

(a). According to data from diagram, we have 60.0 °A – (–30.0 °A) = 130.0 °A –20.0 °B 90.0 ° A = 110.0 °B 1.0 °A =( 11/9 ) °B (b). 40.0 °A = 40.0 ×(11/9) °B 40.0 °A = 48.89 °B
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