Answer
a) 8.5 $\times$ $10^{4}$ N/m
b) 290 N
Work Step by Step
a) $F_{app}$ = k$\Delta$x
670 = k(0.0079)
k $\approx$ 8.5 $\times$ $10^{4}$ N/m
b) $F_{app}$ = k$\Delta$x
= 8.5 $\times$ $10^{4}$ $\times$ 0.0034
$\approx$ 290 N
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