Answer
(d)D
Work Step by Step
Since all pendulums are physical pendulum so time period is independent of mass and is given as
$T=2π\sqrt{\frac{l}{g}}$
$\implies \omega = \frac{2π}{T}=\sqrt{\frac{g}{l}}$
Since $g$ is constant so pendulum with large$l$ will have smallest $\omega$.
Thus D pendulum will have smallest angular frequency.
