Answer
$\text{Clock based on Simple pendulum will become more inaccurate }$
$\text{when carried to the top of a high mountain.}$
Work Step by Step
$\text{Time period of a simple pendulum is given by:}$
$$T = 2\pi \sqrt{\frac{L}{g}}$$
$\text{Time period of a particle performing SHM on a spring is given by:}$
$$T = 2\pi \sqrt{\frac{m}{k}}$$
$\text{Where all terms have their usual meaning}$
$\text{m, k and L depend on the material used and not on the height}$
$\text{at which SHM occurs.}$
$\text{But g depends on height and as we move away from earth g decreases.}$
$\text{Therefore,Clock based on Simple pendulum will become more }$
$\text{inaccurate as we go above the ground.}$
